document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=120242>Question 120242</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve for all values of x that satisfy the equation x/x+3=5/x+7<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #88112 by </B><A HREF=/tutors/aboutme.mpl?userid=madhan_math><B>madhan_math(34)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=madhan_math><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=madhan_math><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=88112\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x/x+3=5/x+7<BR>\n" );
document.write( "solution:<BR>\n" );
document.write( "Taking x as the L.C.M. of both side then denominator x will be cancelled.<BR>\n" );
document.write( "Now we have x+3x=5+7x.<BR>\n" );
document.write( "This implies -3x=5.<BR>\n" );
document.write( "Therefore x has the value x=-5/3. </SPAN>\n" );
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