document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=120190>Question 120190</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a train leaves Havre at 5:30 and heads west at 40/mph. Half an hour later another train leaves Havre heading east at 60/mph what time will it be when the two trains are 200 miles apart </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #88073 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=88073\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 40T+60(T-.5)=200<BR>\n" );
document.write( "40T+60T-30=200<BR>\n" );
document.write( "100T=200+30<BR>\n" );
document.write( "100T=230<BR>\n" );
document.write( "T=230/100<BR>\n" );
document.write( "T=2.3 OR 2 HOURS & 18 MINUTES (5:30+2:18=7:48) THEY WILL BE 200 MILES APART.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "40*2.3+60(2.3-.5)=200<BR>\n" );
document.write( "92+60*1.8=200<BR>\n" );
document.write( "92+108=200<BR>\n" );
document.write( "200=200<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );