document.write( "Question 120128: 6x+3y=-2
\n" ); document.write( "9y+10x=-2\r
\n" ); document.write( "\n" ); document.write( "I have to solve this problem using elimination and I don't understand this at all could someone please help me!
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Algebra.Com's Answer #88045 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition

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\n" ); document.write( " Lets start with the given system of linear equations
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\n" ); document.write( " \"6%2Ax%2B3%2Ay=-2\"
\n" ); document.write( " \"10%2Ax%2B9%2Ay=-2\"
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\n" ); document.write( " In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).
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\n" ); document.write( " So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.
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\n" ); document.write( " So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 6 and 10 to some equal number, we could try to get them to the LCM.
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\n" ); document.write( " Since the LCM of 6 and 10 is 30, we need to multiply both sides of the top equation by 5 and multiply both sides of the bottom equation by -3 like this:
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\n" ); document.write( " \"5%2A%286%2Ax%2B3%2Ay%29=%28-2%29%2A5\" Multiply the top equation (both sides) by 5
\n" ); document.write( " \"-3%2A%2810%2Ax%2B9%2Ay%29=%28-2%29%2A-3\" Multiply the bottom equation (both sides) by -3
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\n" ); document.write( " So after multiplying we get this:
\n" ); document.write( " \"30%2Ax%2B15%2Ay=-10\"
\n" ); document.write( " \"-30%2Ax-27%2Ay=6\"
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\n" ); document.write( " Notice how 30 and -30 add to zero (ie \"30%2B-30=0\")
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\n" ); document.write( " Now add the equations together. In order to add 2 equations, group like terms and combine them
\n" ); document.write( " \"%2830%2Ax-30%2Ax%29%2B%2815%2Ay-27%2Ay%29=-10%2B6\"
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\n" ); document.write( " \"%2830-30%29%2Ax%2B%2815-27%29y=-10%2B6\"
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\n" ); document.write( " \"cross%2830%2B-30%29%2Ax%2B%2815-27%29%2Ay=-10%2B6\" Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether.
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\n" ); document.write( " So after adding and canceling out the x terms we're left with:
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\n" ); document.write( " \"-12%2Ay=-4\"
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\n" ); document.write( " \"y=-4%2F-12\" Divide both sides by \"-12\" to solve for y
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\n" ); document.write( " \"y=1%2F3\" Reduce
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\n" ); document.write( " Now plug this answer into the top equation \"6%2Ax%2B3%2Ay=-2\" to solve for x
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\n" ); document.write( " \"6%2Ax%2B3%281%2F3%29=-2\" Plug in \"y=1%2F3\"
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\n" ); document.write( " \"6%2Ax%2B3%2F3=-2\" Multiply
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\n" ); document.write( " \"6%2Ax%2B1=-2\" Reduce
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\n" ); document.write( " \"6%2Ax=-2-1\" Subtract \"1\" from both sides
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\n" ); document.write( " \"6%2Ax=-3\" Combine the terms on the right side
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\n" ); document.write( " \"cross%28%281%2F6%29%286%29%29%2Ax=%28-3%29%281%2F6%29\" Multiply both sides by \"1%2F6\". This will cancel out \"6\" on the left side.
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\n" ); document.write( " \"x=-1%2F2\" Multiply the terms on the right side
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\n" ); document.write( " So our answer is
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\n" ); document.write( " \"x=-1%2F2\", \"y=1%2F3\"
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\n" ); document.write( " which also looks like
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\n" ); document.write( " (\"-1%2F2\", \"1%2F3\")
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\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
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\n" ); document.write( " \"6%2Ax%2B3%2Ay=-2\"
\n" ); document.write( " \"10%2Ax%2B9%2Ay=-2\"
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\n" ); document.write( " we get
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\n" ); document.write( " graph of \"6%2Ax%2B3%2Ay=-2\" (red) \"10%2Ax%2B9%2Ay=-2\" (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle).
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\n" ); document.write( " and we can see that the two equations intersect at (\"-1%2F2\",\"1%2F3\"). This verifies our answer.
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