document.write( "Question 120131: 7x-y=10
\n" ); document.write( "x=2y-6\r
\n" ); document.write( "\n" ); document.write( "I have to solve this problem using substitution and I don't understand and I'm really confused could someone please help me?
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Algebra.Com's Answer #88037 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "Start with the given system\r
\n" ); document.write( "\n" ); document.write( "\"7x-y=10\"
\n" ); document.write( "\"x=2y-6\"\r
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\n" ); document.write( "\n" ); document.write( "\"7%282y-6%29-y=10\" Plug in \"x=2y-6\" into the first equation. In other words, replace each \"x\" with \"2y-6\". Notice we've eliminated the \"x\" variables. So we now have a simple equation with one unknown.\r
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\n" ); document.write( "\n" ); document.write( "\"14y-42-y=10\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"13y-42=10\" Combine like terms on the left side\r
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\n" ); document.write( "\n" ); document.write( "\"13y=10%2B42\"Add 42 to both sides\r
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\n" ); document.write( "\n" ); document.write( "\"13y=52\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"y=%2852%29%2F%2813%29\" Divide both sides by 13 to isolate y\r
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\n" ); document.write( "\n" ); document.write( "\"y=4\" Divide\r
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\n" ); document.write( "\n" ); document.write( "Now that we know that \"y=4\", we can plug this into \"x=2y-6\" to find \"x\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=2%284%29-6\" Substitute \"4\" for each \"y\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=2\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "So our answer is \"x=2\" and \"y=4\"
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