document.write( "Question 120133: I don't really understand how to do the substitution method.
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Algebra.Com's Answer #88036 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: Solving a linear system of equations by subsitution

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\n" ); document.write( " Lets start with the given system of linear equations
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\n" ); document.write( " \"2%2Ax-3%2Ay=-25\"
\n" ); document.write( " \"3%2Ax%2B1%2Ay=1\"
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\n" ); document.write( " Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to choose y.
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\n" ); document.write( " Solve for y for the first equation
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\n" ); document.write( " \"-3%2Ay=-25-2%2Ax\"Subtract \"2%2Ax\" from both sides
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\n" ); document.write( " \"y=%28-25-2%2Ax%29%2F-3\" Divide both sides by -3.
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\n" ); document.write( " Which breaks down and reduces to
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\n" ); document.write( " \"y=25%2F3%2B%282%2F3%29%2Ax\" Now we've fully isolated y
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\n" ); document.write( " Since y equals \"25%2F3%2B%282%2F3%29%2Ax\" we can substitute the expression \"25%2F3%2B%282%2F3%29%2Ax\" into y of the 2nd equation. This will eliminate y so we can solve for x.
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\n" ); document.write( " \"3%2Ax%2B1%2Ahighlight%28%2825%2F3%2B%282%2F3%29%2Ax%29%29=1\" Replace y with \"25%2F3%2B%282%2F3%29%2Ax\". Since this eliminates y, we can now solve for x.
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\n" ); document.write( " \"3%2Ax%2B1%2A%2825%2F3%29%2B1%282%2F3%29x=1\" Distribute 1 to \"25%2F3%2B%282%2F3%29%2Ax\"
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\n" ); document.write( " \"3%2Ax%2B25%2F3%2B%282%2F3%29%2Ax=1\" Multiply
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\n" ); document.write( " \"3%2Ax%2B25%2F3%2B%282%2F3%29%2Ax=1\" Reduce any fractions
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\n" ); document.write( " \"3%2Ax%2B%282%2F3%29%2Ax=1-25%2F3\" Subtract \"25%2F3\" from both sides
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\n" ); document.write( " \"3%2Ax%2B%282%2F3%29%2Ax=3%2F3-25%2F3\" Make 1 into a fraction with a denominator of 3
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\n" ); document.write( " \"3%2Ax%2B%282%2F3%29%2Ax=-22%2F3\" Combine the terms on the right side
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\n" ); document.write( " \"%289%2F3%29%2Ax%2B%282%2F3%29x=-22%2F3\" Make 3 into a fraction with a denominator of 3
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\n" ); document.write( " \"%2811%2F3%29%2Ax=-22%2F3\" Now combine the terms on the left side.
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\n" ); document.write( " \"cross%28%283%2F11%29%2811%2F3%29%29x=%28-22%2F3%29%283%2F11%29\" Multiply both sides by \"3%2F11\". This will cancel out \"11%2F3\" and isolate x
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\n" ); document.write( " So when we multiply \"-22%2F3\" and \"3%2F11\" (and simplify) we get
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\n" ); document.write( " \"x=-2\" <---------------------------------One answer
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\n" ); document.write( " Now that we know that \"x=-2\", lets substitute that in for x to solve for y
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\n" ); document.write( " \"3%28-2%29%2B1%2Ay=1\" Plug in \"x=-2\" into the 2nd equation
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\n" ); document.write( " \"-6%2B1%2Ay=1\" Multiply
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\n" ); document.write( " \"1%2Ay=1%2B6\"Add \"6\" to both sides
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\n" ); document.write( " \"1%2Ay=7\" Combine the terms on the right side
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\n" ); document.write( " \"cross%28%281%2F1%29%281%29%29%2Ay=%287%2F1%29%281%2F1%29\" Multiply both sides by \"1%2F1\". This will cancel out 1 on the left side.
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\n" ); document.write( " \"y=7%2F1\" Multiply the terms on the right side
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\n" ); document.write( " \"y=7\" Reduce
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\n" ); document.write( " So this is the other answer
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\n" ); document.write( " \"y=7\"<---------------------------------Other answer
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\n" ); document.write( " So our solution is
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\n" ); document.write( " \"x=-2\" and \"y=7\"
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\n" ); document.write( " which can also look like
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\n" ); document.write( " (\"-2\",\"7\")
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\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
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\n" ); document.write( " \"2%2Ax-3%2Ay=-25\"
\n" ); document.write( " \"3%2Ax%2B1%2Ay=1\"
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\n" ); document.write( " we get
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\n" ); document.write( " graph of \"2%2Ax-3%2Ay=-25\" (red) and \"3%2Ax%2B1%2Ay=1\" (green) (hint: you may have to solve for y to graph these) intersecting at the blue circle.
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\n" ); document.write( " and we can see that the two equations intersect at (\"-2\",\"7\"). This verifies our answer.
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\n" ); document.write( " Plug in (\"-2\",\"7\") into the system of equations
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\n" ); document.write( " Let \"x=-2\" and \"y=7\". Now plug those values into the equation \"2%2Ax-3%2Ay=-25\"
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\n" ); document.write( " \"2%2A%28-2%29-3%2A%287%29=-25\" Plug in \"x=-2\" and \"y=7\"
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\n" ); document.write( " \"-4-21=-25\" Multiply
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\n" ); document.write( " \"-25=-25\" Add
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\n" ); document.write( " \"-25=-25\" Reduce. Since this equation is true the solution works.
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\n" ); document.write( " So the solution (\"-2\",\"7\") satisfies \"2%2Ax-3%2Ay=-25\"
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\n" ); document.write( " Let \"x=-2\" and \"y=7\". Now plug those values into the equation \"3%2Ax%2B1%2Ay=1\"
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\n" ); document.write( " \"3%2A%28-2%29%2B1%2A%287%29=1\" Plug in \"x=-2\" and \"y=7\"
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\n" ); document.write( " \"-6%2B7=1\" Multiply
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\n" ); document.write( " \"1=1\" Add
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\n" ); document.write( " \"1=1\" Reduce. Since this equation is true the solution works.
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\n" ); document.write( " So the solution (\"-2\",\"7\") satisfies \"3%2Ax%2B1%2Ay=1\"
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\n" ); document.write( " Since the solution (\"-2\",\"7\") satisfies the system of equations
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\n" ); document.write( " \"2%2Ax-3%2Ay=-25\"
\n" ); document.write( " \"3%2Ax%2B1%2Ay=1\"
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\n" ); document.write( " this verifies our answer.
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