document.write( "Question 120058: if their are 34times more nickles then dimes and 18times more pennies then dimes. how nickles do i have if their is $104.94. \n" ); document.write( "
Algebra.Com's Answer #88026 by ankor@dixie-net.com(22740)\"\" \"About 
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If there are 34 times more nickels than dimes
\n" ); document.write( " n = 34d
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\n" ); document.write( " and 18 times more pennies than dimes.
\n" ); document.write( " p = 18d
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\n" ); document.write( ".01p + .05n + .10d = 104.94
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\n" ); document.write( "Substitute 34d for n and 18d + p and solve for d:
\n" ); document.write( ":
\n" ); document.write( ".01(18d) + .05(34d) + .10d = 104.94
\n" ); document.write( ":
\n" ); document.write( ".18d + 1.7d + .10d = 104.94
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\n" ); document.write( "1.98d = 104.94
\n" ); document.write( "d = \"104.94%2F1.98\"
\n" ); document.write( "d = 53 dimes
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\n" ); document.write( "how many nickels do I have, if there is $104.94?
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\n" ); document.write( "n = 34(53)
\n" ); document.write( "n = 1802 nickels
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\n" ); document.write( "Find pennies
\n" ); document.write( "p = 18(53)
\n" ); document.write( "p = 954 pennies
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\n" ); document.write( "Check solution
\n" ); document.write( ".10(53) + .05(1802) + .01(954) =
\n" ); document.write( "5.30 + 90.10 + 9.54 = 104.94; confirms our solutions \n" ); document.write( "
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