document.write( "Question 119977This question is from textbook
\n" ); document.write( ": Sharon drove for part of a 150 km trop at 45 km/h and the rest of the trop at 75km/h. How far did she drive at each speed if the entire trip took her 2h 40 mins. \n" ); document.write( "
Algebra.Com's Answer #88007 by ankor@dixie-net.com(22740)\"\" \"About 
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Sharon drove for part of a 150 km trop at 45 km/h and the rest of the trop at 75km/h. How far did she drive at each speed if the entire trip took her 2h 40 mins.
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\n" ); document.write( "Let d = distance driven at 45 km/h
\n" ); document.write( "Then
\n" ); document.write( "(150-d) = distance driven at 75 km/h
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\n" ); document.write( "Change 2:40 to hrs: 120 + 40 = 160 min = 160/60 = \"8%2F3\" hrs
\n" ); document.write( ":
\n" ); document.write( "Write a time equation: Time = distance/speed
\n" ); document.write( ":
\n" ); document.write( "Time at 45 km/hr + time at 75km/hr = \"8%2F3\" hrs
\n" ); document.write( "\"d%2F45\" + \"%28%28150-d%29%29%2F75\" = \"8%2F3\"
\n" ); document.write( ":
\n" ); document.write( "Multiply equation by 450 to get rid of those annoying denominators:
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\n" ); document.write( "450*\"d%2F45\" + 450*\"%28%28150-d%29%29%2F75\" = 450*\"8%2F3\"
\n" ); document.write( ":
\n" ); document.write( "Cancel out the denominators and we have:
\n" ); document.write( "10d + 6(150 - d) = 150(8)
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\n" ); document.write( "10d + 900 - 6d = 1200
\n" ); document.write( ":
\n" ); document.write( "10d - 6d = 1200 - 900
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\n" ); document.write( "4d = 300
\n" ); document.write( ":
\n" ); document.write( "d = \"300%2F4\"
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\n" ); document.write( "d = 75 km at 45 km/hr
\n" ); document.write( "then
\n" ); document.write( "150 - 75 = 75 km at 75 km/hr
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\n" ); document.write( "Check solution by finding the time:
\n" ); document.write( "75/45 + 75/75 =
\n" ); document.write( "\"5%2F3\" + \"3%2F3\" = \"8%2F3\"; confirms our solutions
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