document.write( "Question 119977This question is from textbook
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document.write( ": Sharon drove for part of a 150 km trop at 45 km/h and the rest of the trop at 75km/h. How far did she drive at each speed if the entire trip took her 2h 40 mins. \n" );
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Algebra.Com's Answer #88007 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Sharon drove for part of a 150 km trop at 45 km/h and the rest of the trop at 75km/h. How far did she drive at each speed if the entire trip took her 2h 40 mins. \n" ); document.write( ": \n" ); document.write( "Let d = distance driven at 45 km/h \n" ); document.write( "Then \n" ); document.write( "(150-d) = distance driven at 75 km/h \n" ); document.write( ": \n" ); document.write( "Change 2:40 to hrs: 120 + 40 = 160 min = 160/60 = \n" ); document.write( ": \n" ); document.write( "Write a time equation: Time = distance/speed \n" ); document.write( ": \n" ); document.write( "Time at 45 km/hr + time at 75km/hr = \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Multiply equation by 450 to get rid of those annoying denominators: \n" ); document.write( ": \n" ); document.write( "450* \n" ); document.write( ": \n" ); document.write( "Cancel out the denominators and we have: \n" ); document.write( "10d + 6(150 - d) = 150(8) \n" ); document.write( ": \n" ); document.write( "10d + 900 - 6d = 1200 \n" ); document.write( ": \n" ); document.write( "10d - 6d = 1200 - 900 \n" ); document.write( ": \n" ); document.write( "4d = 300 \n" ); document.write( ": \n" ); document.write( "d = \n" ); document.write( ": \n" ); document.write( "d = 75 km at 45 km/hr \n" ); document.write( "then \n" ); document.write( "150 - 75 = 75 km at 75 km/hr \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution by finding the time: \n" ); document.write( "75/45 + 75/75 = \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |