document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=120073>Question 120073</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 25-ft ladder is placed 8 ft from the base of the house. How high up the side of the house can the ladder reach? Round your answer to the nearest foot.Thanks a lot </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #88003 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=88003\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> WHAT YOU HAVE IS A RIGHT TRIANGLE WITH AN HYPOTENUSE=25 & 1 SIDE=8.<BR>\n" );
document.write( "25^2=8^2+X^2 FOR THE OTHER SIDE OR HIGHT OF THE LADDER.<BR>\n" );
document.write( "625=64+X^2<BR>\n" );
document.write( "X^2=625-64<BR>\n" );
document.write( "X^2=561<BR>\n" );
document.write( "X=SQRT561<BR>\n" );
document.write( "X=23.68 OR 24 FEET UP THE SIDE OF THE HOUSE. </SPAN>\n" );
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