document.write( "Question 120078: The path of a falling object is given by the function s=-16t^2+v0t+s0 where v0 represents the initial velocity in ft/sec and s0 represents the initial height in feet.
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document.write( "If a rock is thrown upward with an initial velocity of 32 feet per second from the top of a 40-foot building, write the height (s) equation using this information. \r
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document.write( "How high is the rock after 0.5 second?\r
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document.write( "After how many seconds will the graph reach maximum height? \r
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document.write( "What is the maximum height?
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Algebra.Com's Answer #88002 by stanbon(75887) ![]() You can put this solution on YOUR website! The path of a falling object is given by the function s=-16t^2+v0t+s0 where v0 represents the initial velocity in ft/sec and s0 represents the initial height in feet. \n" ); document.write( "If a rock is thrown upward with an initial velocity of 32 feet per second from the top of a 40-foot building, write the height (s) equation using this information. \n" ); document.write( "--------- \n" ); document.write( "EQUATION: \n" ); document.write( "h(t)=-16t^2+32t+40 \n" ); document.write( "--------------------- \n" ); document.write( "How high is the rock after 0.5 second? \n" ); document.write( "Find h(0.5) = 52 ft \n" ); document.write( "------------------------- \n" ); document.write( "After how many seconds will the graph reach maximum height? \n" ); document.write( "Maximum height when t = -b/2a = -32/(-2*16)= 1 second \n" ); document.write( "--------------- \n" ); document.write( "What is the maximum height? \n" ); document.write( "Find h(1) = -16+32+40 = 56 ft \n" ); document.write( "============= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |