document.write( "Question 120072: Dear Tutors,\r
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\n" ); document.write( "\n" ); document.write( "The area of a rectangular playground is 2,700 ft2. The length is 3 times the width. What are the dimensions of the play ground? Please help!!!THANKS
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Algebra.Com's Answer #87997 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
First we know that the area of a rectangle is given by \"A=lw\", so we can write:\r
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\n" ); document.write( "\n" ); document.write( "\"lw=2700\"\r
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\n" ); document.write( "\n" ); document.write( "But we also know that the length, \"l\", is three times the width \"w\", so we can write:\r
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\n" ); document.write( "\n" ); document.write( "\"l=3w\"\r
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\n" ); document.write( "\n" ); document.write( "Now we can change the first equation to read:\r
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\n" ); document.write( "\n" ); document.write( "\"3w%2Aw=2700\", or \"3w%5E2=2700\"\r
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\n" ); document.write( "\n" ); document.write( "Divide both sides by 3\r
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\n" ); document.write( "\n" ); document.write( "\"w%5E2=900\"\r
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\n" ); document.write( "\n" ); document.write( "Take the square root of both sides:\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%28w%5E2%29=sqrt%28900%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"w=30\" or \"w=-30\". However, since we are looking for a measure of length, we can exclude the \"w=-30\" result.\r
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\n" ); document.write( "\n" ); document.write( "Since we know that \"l=3w\", we now know that \"l=3%2A30=90\".\r
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\n" ); document.write( "\n" ); document.write( "So the dimensions of the playground are 90 feet by 30 feet.\r
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\n" ); document.write( "\n" ); document.write( "Check:\r
\n" ); document.write( "\n" ); document.write( "\"90%2A30=2700\" and \"3%2A30=90\": Checks!\r
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\n" ); document.write( "\n" ); document.write( "Hope that helps.
\n" ); document.write( "John\r
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