document.write( "Question 120040: \r
\n" ); document.write( "\n" ); document.write( "Two cyclists, 79 mi apart, start riding towards each other at the same time. One cycles twice as fast as the other. If they meet 1 hr later, at what average speed is each cyclist traveling?\r
\n" ); document.write( "\n" ); document.write( "_____mi/hr(slower cyclist)\r
\n" ); document.write( "\n" ); document.write( "_____mi/hr(faster cyclist)
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Algebra.Com's Answer #87987 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
X+2X=79
\n" ); document.write( "3X=79
\n" ); document.write( "X=79/3
\n" ); document.write( "X=26.33 MPH FOR THE SLOWEST BIKER.
\n" ); document.write( "2*26.33=52.67 MPH FOR THE FASTER BIKER.
\n" ); document.write( "PROOF
\n" ); document.write( "26.33+52.67=79
\n" ); document.write( "79=79
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