document.write( "Question 120040: \r
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document.write( "Two cyclists, 79 mi apart, start riding towards each other at the same time. One cycles twice as fast as the other. If they meet 1 hr later, at what average speed is each cyclist traveling?\r
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document.write( "_____mi/hr(slower cyclist)\r
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document.write( "_____mi/hr(faster cyclist)
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Algebra.Com's Answer #87987 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! X+2X=79 \n" ); document.write( "3X=79 \n" ); document.write( "X=79/3 \n" ); document.write( "X=26.33 MPH FOR THE SLOWEST BIKER. \n" ); document.write( "2*26.33=52.67 MPH FOR THE FASTER BIKER. \n" ); document.write( "PROOF \n" ); document.write( "26.33+52.67=79 \n" ); document.write( "79=79 \n" ); document.write( " |