document.write( "Question 120042: If Ben invests $5000 at 5% interest per year, how much additional money must he
\n" ); document.write( "invest at 6.5% annual interest to ensure that the interest he receives each year is 5.5% of the total amount invested?\r
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Algebra.Com's Answer #87982 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
5000*.05+.065x=.055(5000+x)
\n" ); document.write( "250+.065x=275+.055x
\n" ); document.write( ".065x-.055x=275-250
\n" ); document.write( ".01x=25
\n" ); document.write( "x=25/.01
\n" ); document.write( "x=2500 amount of additional money to be invested @ 6.5%.
\n" ); document.write( "proof
\n" ); document.write( "5000*.05+.065*2500=.055(5000+2500)
\n" ); document.write( "250+162.5=.055*7500
\n" ); document.write( "412.5=412.5\r
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