document.write( "Question 120042: If Ben invests $5000 at 5% interest per year, how much additional money must he
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document.write( "invest at 6.5% annual interest to ensure that the interest he receives each year is 5.5% of the total amount invested?\r
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Algebra.Com's Answer #87982 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! 5000*.05+.065x=.055(5000+x) \n" ); document.write( "250+.065x=275+.055x \n" ); document.write( ".065x-.055x=275-250 \n" ); document.write( ".01x=25 \n" ); document.write( "x=25/.01 \n" ); document.write( "x=2500 amount of additional money to be invested @ 6.5%. \n" ); document.write( "proof \n" ); document.write( "5000*.05+.065*2500=.055(5000+2500) \n" ); document.write( "250+162.5=.055*7500 \n" ); document.write( "412.5=412.5\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |