document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=120037>Question 120037</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the general term of a sequence whose first four terms are given.\r<BR>\n" );
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document.write( "28.)\r<BR>\n" );
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document.write( "2, -1,-4,-7,…\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #87981 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=87981\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the general term of a sequence whose first four terms are given. \r<BR>\n" );
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document.write( "2, -1,-4,-7,… <BR>\n" );
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document.write( "The sequence has a common difference of d=-3 so it is arithmetic.<BR>\n" );
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document.write( "Formula: a(n)=a(1)+(n-1)d<BR>\n" );
document.write( "Your sequence formula:<BR>\n" );
document.write( "a(n)=2+(n-1)(-3)<BR>\n" );
document.write( "a(n)=2-3n+3<BR>\n" );
document.write( "a(n)=5-3n<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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