document.write( "Question 120045: The sum of three consecutive odd integers is no less than 57. Find the possible second odd integers. \n" ); document.write( "
Algebra.Com's Answer #87970 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! The sum of three consecutive odd integers is no less than 57.\ Fin0d the possible second odd integers.\r \n" ); document.write( "\n" ); document.write( "FIRST odd integer = x \n" ); document.write( "SECOND odd integer = x+2 \n" ); document.write( "THIRD odd integer = x+4\r \n" ); document.write( "\n" ); document.write( "The sum of three consecutive odd integers is no less than 57.\r \n" ); document.write( "\n" ); document.write( "\"No less than 57\" means \"Greater than or equal to 57\".\r \n" ); document.write( "\n" ); document.write( "So we add the three by putting plusses between them \n" ); document.write( "and then put a \"less than or equal to\" between that and 57:P \r \n" ); document.write( "\n" ); document.write( "x + x+2 + x+4 > 57\r \n" ); document.write( "\n" ); document.write( "Solving:\r \n" ); document.write( "\n" ); document.write( "3x + 6 > 57\r \n" ); document.write( "\n" ); document.write( "3x > 57 - 6\r \n" ); document.write( "\n" ); document.write( "3x > 51\r \n" ); document.write( "\n" ); document.write( "x > 17\r \n" ); document.write( "\n" ); document.write( "So the possibilities for the FIRST odd integer, x, are odd integers \n" ); document.write( "17 or greater,\r \n" ); document.write( "\n" ); document.write( "therefore the answer to your question is\r \n" ); document.write( "\n" ); document.write( "The possibilities for the SECOND odd integer, x+2, are odd integers \n" ); document.write( "19 or greater.\r \n" ); document.write( "\n" ); document.write( "Edwin\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |