document.write( "Question 119999This question is from textbook Beginning and Intermediate Algebra
\n" );
document.write( ": A river boat tour begins by going 60 miles upstream against a 5 mph current. Then the boat turns around and returns with the current. What still-water speed should the captain use to complete the tour in 5 hours? \n" );
document.write( "
Algebra.Com's Answer #87950 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A river boat tour begins by going 60 miles upstream against a 5 mph current. Then the boat turns around and returns with the current. What still-water speed should the captain use to complete the tour in 5 hours? \n" ); document.write( ": \n" ); document.write( "Dear Student, I think I interpreted this problem wrong. It seems they want to \n" ); document.write( "know the speed required to return to the beginning (60 mi) in 5 hrs \n" ); document.write( ": \n" ); document.write( "Let s = still water speed \n" ); document.write( "then \n" ); document.write( "(s+5) = speed downstream \n" ); document.write( ": \n" ); document.write( "Write a time equation: Time = Distance/speed \n" ); document.write( ": \n" ); document.write( "Time down stream = 5 h \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Multiply equation by (s+5) to get rid of the denominators, results: \n" ); document.write( "60 = 5(s+5) \n" ); document.write( ": \n" ); document.write( "60 = 5s + 25 \n" ); document.write( ": \n" ); document.write( "5s = 60 - 25 \n" ); document.write( "5s = 35 \n" ); document.write( "s = 35/5 \n" ); document.write( "s = 7 mph still water speed to return in 5 hours \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check by finding the distance going (7+5) mph for 5 hrs \n" ); document.write( "12*5 = 80; confirms our solution \n" ); document.write( ": \n" ); document.write( "I truly regret giving you wrong information. Ankor \n" ); document.write( " |