document.write( "Question 120012: The sum of the digits of a two-digit number is 11. If the digits are reversed, the new number is 45 more than the original number. Find the number. \n" ); document.write( "
Algebra.Com's Answer #87944 by stanbon(75887)\"\" \"About 
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The sum of the digits of a two-digit number is 11. If the digits are reversed, the new number is 45 more than the original number. Find the number.
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\n" ); document.write( "Let the two-digit number be 10t+u where t is the tens digit and u the units digit.
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\n" ); document.write( "EQUATION:
\n" ); document.write( "t+u = 11
\n" ); document.write( "10u+t = 10t+u + 45
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\n" ); document.write( "Rearrange the equations:
\n" ); document.write( "t+u = 11
\n" ); document.write( "9t-9u = -45
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\n" ); document.write( "Simplify:
\n" ); document.write( "t+u = 11
\n" ); document.write( "t-u = -5
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\n" ); document.write( "Add the equations to solve for \"t\":
\n" ); document.write( "2t = 6
\n" ); document.write( "t = 3
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\n" ); document.write( "Substitute to solve for \"u\":
\n" ); document.write( "3+u = 11
\n" ); document.write( "u = 8
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\n" ); document.write( "The original number is 38
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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