document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=119985>Question 119985</A>: <I><SPAN STYLE=\"word-break: break-all;\">  I need help solving a problem that says, write an equation of the line that is \r<BR>\n" );
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document.write( "perpendicular to the line 5y + 2x = 13 and  <BR>\n" );
document.write( "passes through the (6, 2). Write the answer in slope-intercept form or standard form. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #87930 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=87930\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5Y+2X=13<BR>\n" );
document.write( "5Y=-2X+13<BR>\n" );
document.write( "Y=-2X/5+13/5 THUS THIS LINE HAS A SLOPE OF -2/5. (RED LINE)<BR>\n" );
document.write( "FOR THE PERPENDICULAR LINE THE SLOPE IS THE NEGATIVE RECIPRICAL OF THIS SLOPE OR 5/2.<BR>\n" );
document.write( "USING THE POINT(6,2 & THE SLOPE OF 5/2 WE SOLVE THE LINE EQUATION FOR THE Y INTERCEPT(b)<BR>\n" );
document.write( "2=5/2*6+b<BR>\n" );
document.write( "2=30/2+b<BR>\n" );
document.write( "b=2-15<BR>\n" );
document.write( "b=-13 FOR THIS Y INTERCEPT.<BR>\n" );
document.write( "y=5x/2-13 (GREEN LINE)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+400%2C+400%2C+-6%2C+15%2C+-15%2C+15%2C+y+=+-2x%2F5+%2B13%2C+y+=+5x%2F2+-13%29+ ALIGN=MIDDLE  ALT=\"+graph%28+400%2C+400%2C+-6%2C+15%2C+-15%2C+15%2C+y+=+-2x%2F5+%2B13%2C+y+=+5x%2F2+-13%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > (graph 400x400 pixels, x from -6 to 15, y from -15 to 15, of TWO functions y = -2x/5 +13 and y = 5x/2 -13).  </SPAN>\n" );
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