document.write( "Question 119998: The length of a rectangle is 3 cm more than 5 times its width. If the area of the rectangle is 62 cm^2, find the dimensions of the rectangle to the nearest thousandth. \n" ); document.write( "

Algebra.Com's Answer #87925 by checkley71(8403) $\"\"$ $\"About$

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LENGTH=5W+3
\n" ); document.write( "WIDTH=W
\n" ); document.write( "62=W(5W+3)
\n" ); document.write( "62=5W^2+3W
\n" ); document.write( "5W^2+3W-62=0
\n" ); document.write( "USING THE QUADRATIC EQUATION $\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"$ WE GET:
\n" ); document.write( "W=(-3+-SQRT[3^2-4*5*-62])/2*5
\n" ); document.write( "W=(-3+-SQRT[9+1240])/10
\n" ); document.write( "W=(-3+-SQRT1249)/10
\n" ); document.write( "W=(-3+-35.341)/10
\n" ); document.write( "W=(-3+35.341)/10
\n" ); document.write( "W=32.341/10
\n" ); document.write( "W=3.234 ANSWER FOR THE WIDTH.
\n" ); document.write( "L=5*3.234+3
\n" ); document.write( "L=16.17+3
\n" ); document.write( "L=19.17 ANSWER FOR THE LENGTH.
\n" ); document.write( "PROOF
\n" ); document.write( "3.234*19.17=62
\n" ); document.write( "62=62 \n" ); document.write( "

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