document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=119932>Question 119932</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 2 cm more than 5 times its width. If the area of the rectagle is 68cm^2, find the dimensions of the rectagle to the nearest thousandth. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #87909 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=87909\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> LENGTH=5W+2<BR>\n" );
document.write( "WIDTH=W<BR>\n" );
document.write( "AREA=W*L<BR>\n" );
document.write( "68=W(5W+2)<BR>\n" );
document.write( "68=5W^2+2W<BR>\n" );
document.write( "5W^2+2W-68=0<BR>\n" );
document.write( "USING THE QUADRATIC EQUATION:<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ ALIGN=MIDDLE  ALT=\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > WE GET:<BR>\n" );
document.write( "X=(-2+-SQRT[2^2-4*5*-68])/2*5<BR>\n" );
document.write( "X=(-2+-SQRT[4+1360])/10<BR>\n" );
document.write( "X=(-2+-SQRT1364)/10<BR>\n" );
document.write( "X=(-2+-36.932)/10<BR>\n" );
document.write( "X=(-2+36.932)/10<BR>\n" );
document.write( "X=34.932/10<BR>\n" );
document.write( "X=3.493 ANSWER<BR>\n" );
document.write( "X=(-2-36.932)/10<BR>\n" );
document.write( "X=-38.932/10<BR>\n" );
document.write( "X=-3.893 ANSWER. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );