document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=119901>Question 119901</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0321233883/algebrahomeworkh>Elementary Algebra Concepts and Applications</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> 8-(2x3-9)=<BR>\n" );
document.write( "Please take me step by step on how to solve this.\r<BR>\n" );
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document.write( "2 to the 4th power plus 2 cubed - 10 divided by (-1) to the 4th power=<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #87896 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=87896\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since you say solve this, the expression must = 0\r<BR>\n" );
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document.write( "8 - (2x^3 - 9) = 0<BR>\n" );
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document.write( "Removing the brackets changes the signs<BR>\n" );
document.write( "8 - 2x^3 + 9 = 0<BR>\n" );
document.write( "Which is:<BR>\n" );
document.write( "-2x^3 + 17 = 0<BR>\n" );
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document.write( "-2x^3 = -17; subtracted 17 from both sides<BR>\n" );
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document.write( "Get rid of the negatives, multiply both sides by -1<BR>\n" );
document.write( "2x^3 = +17<BR>\n" );
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document.write( "x^3 = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=17%2F2 ALIGN=MIDDLE  ALT=\"17%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >; divided both sides by 2<BR>\n" );
document.write( "x^3 = 8.5<BR>\n" );
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document.write( "x = Cube root(8.5)<BR>\n" );
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document.write( "x = 2.0408; found 8.5^(1/3) on a calculator<BR>\n" );
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document.write( "Check solution, substitute 2.0408 for x in the original equation:<BR>\n" );
document.write( "8 - (2(2.0408^3) - 9) =<BR>\n" );
document.write( "8 - (2(8.5)-9) = <BR>\n" );
document.write( "8 - (17 - 9)<BR>\n" );
document.write( "8 - 8 = 0 confirms our solution<BR>\n" );
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document.write( "2 to the 4th power plus 2 cubed - 10 divided by (-1) to the 4th power=<BR>\n" );
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document.write( "The problem as I see it:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28%282%5E4+%2B+2%5E3+-+10%29%29%2F%28-1%5E4%29 ALIGN=MIDDLE  ALT=\"%28%282%5E4+%2B+2%5E3+-+10%29%29%2F%28-1%5E4%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "First of all remember that -1 to any even numbered power is + 1 so we can ignore the denominator:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%282%5E4+%2B+2%5E3+-+10%29 ALIGN=MIDDLE  ALT=\"%282%5E4+%2B+2%5E3+-+10%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Find the values of 2^4; 2*2*2*2 = 16, find the value of 2^3: 2*2*2 = 8<BR>\n" );
document.write( "Now we have:<BR>\n" );
document.write( "16 + 8 - 10 = +14<BR>\n" );
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document.write( "Was this enough steps to help you? </SPAN>\n" );
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