document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=119836>Question 119836</A>: <I><SPAN STYLE=\"word-break: break-all;\"> hi, can you help me with this problem?\r<BR>\n" );
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document.write( "A rectangular parcel of land is 40 ft wide. The length of a diagonal between opposite corners is 18 ft more than the length of the parcel. What is the length of the parcel? (Round the answer to one decimal place.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #87892 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=87892\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A rectangular parcel of land is 40 ft wide. The length of a diagonal between opposite corners is 18 ft more than the length of the parcel. What is the length of the parcel? (Round the answer to one decimal place.)<BR>\n" );
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document.write( "Here's what we know:<BR>\n" );
document.write( "W = 40<BR>\n" );
document.write( "L is unknown<BR>\n" );
document.write( "Diagonal = L + 18<BR>\n" );
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document.write( "Using Pythagorus: a^2 + b^2 = c^2<BR>\n" );
document.write( "Let a = 40<BR>\n" );
document.write( "Let b = L<BR>\n" );
document.write( "Let c = (L+18)<BR>\n" );
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document.write( "40^2 + L^2 = (L+18)^2<BR>\n" );
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document.write( "FOIL (L+18)(L+18)<BR>\n" );
document.write( "1600 + L^2 = L^2 + 36L + 324<BR>\n" );
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document.write( "Arrange equation; L's on the left, numerical values on the right<BR>\n" );
document.write( "L^2 - L^2 - 36L = 324 - 1600<BR>\n" );
document.write( "-36L = -1276<BR>\n" );
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document.write( "L = -1276/-36<BR>\n" );
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document.write( "L = +35.4 ft is the length.<BR>\n" );
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document.write( "Check the solution by finding the hypotenuse:<BR>\n" );
document.write( "h = Sqrt(40^2 + 35.4^2) <BR>\n" );
document.write( "h = Sqrt(1600 + 1253.2)<BR>\n" );
document.write( "h = 53.4 ft which is 18 ft greater than the length  <BR>\n" );
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