document.write( "Question 119883: Hi Tutors, Can someone see if I did this problem right and if not can you tell me what I did wrong. Solve the equations.\r
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document.write( "sqrt 4x + 1 + 3 =0\r
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document.write( "sqrt 4x + 1 = -3\r
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document.write( "sqrt 4x + 1^2 =(-3)^2 \r
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document.write( "4x + 1= 9\r
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document.write( "4x = 9 – 1 Subtract \r
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document.write( "4x = 8 Divide by 2\r
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document.write( "x= 2 is the answer\r
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document.write( "How can I check to see if this is the right answer.\r
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document.write( "One more thing I am stuck on this problem because of the x can someone please help.\r
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document.write( "sqrt 2x + 1 + x = 7 \n" );
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Algebra.Com's Answer #87855 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "How can I check to see if this is the right answer. \n" ); document.write( "You can plug this value of \n" ); document.write( "but first notice what you got above: \n" ); document.write( " \n" ); document.write( "This is telling you that what you're squaring on the right is \n" ); document.write( "a negative number, so The square root on the left must be the \n" ); document.write( "negative square root, which, when squared gives a positive \n" ); document.write( "Going back to: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "This is true, one of the square roots of 9 is -3. \n" ); document.write( " \n" ); document.write( "OK \n" ); document.write( " |