document.write( "Question 119883: Hi Tutors, Can someone see if I did this problem right and if not can you tell me what I did wrong. Solve the equations.\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "sqrt 4x + 1 + 3 =0\r
\n" ); document.write( "\n" ); document.write( "sqrt 4x + 1 = -3\r
\n" ); document.write( "\n" ); document.write( "sqrt 4x + 1^2 =(-3)^2 \r
\n" ); document.write( "\n" ); document.write( "4x + 1= 9\r
\n" ); document.write( "\n" ); document.write( "4x = 9 – 1 Subtract \r
\n" ); document.write( "\n" ); document.write( "4x = 8 Divide by 2\r
\n" ); document.write( "\n" ); document.write( "x= 2 is the answer\r
\n" ); document.write( "\n" ); document.write( "How can I check to see if this is the right answer.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "One more thing I am stuck on this problem because of the x can someone please help.\r
\n" ); document.write( "\n" ); document.write( "sqrt 2x + 1 + x = 7
\n" ); document.write( "

Algebra.Com's Answer #87855 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"sqrt%284x+%2B+1%29+%2B+3+=+0\"
\n" ); document.write( "\"sqrt%28+4x+%2B+1%29+=+-3\"
\n" ); document.write( "\"%28sqrt%284x+%2B+1%29%29%5E2+=%28-3%29%5E2\"
\n" ); document.write( "\"4x+%2B+1=+9\"
\n" ); document.write( "\"4x+=+9+%96+1\" Subtract
\n" ); document.write( "\"4x+=+8\" Divide by 2
\n" ); document.write( "\"x+=+2\" is the answer
\n" ); document.write( "How can I check to see if this is the right answer.
\n" ); document.write( "You can plug this value of \"x\" back into the original equation,
\n" ); document.write( "but first notice what you got above:
\n" ); document.write( "\"%28sqrt%284x+%2B+1%29%29%5E2+=%28-3%29%5E2\"
\n" ); document.write( "This is telling you that what you're squaring on the right is
\n" ); document.write( "a negative number, so The square root on the left must be the
\n" ); document.write( "negative square root, which, when squared gives a positive
\n" ); document.write( "Going back to:
\n" ); document.write( "\"sqrt%284x+%2B+1%29+%2B+3+=+0\"
\n" ); document.write( "\"sqrt%284%2A2+%2B+1%29+%2B+3+=+0\"
\n" ); document.write( "\"sqrt%289%29+=+-3\"
\n" ); document.write( "This is true, one of the square roots of 9 is -3.
\n" ); document.write( "\"-3+=+-3\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );