document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=119877>Question 119877</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0028251784/algebrahomeworkh>Glencoe Algebra 2</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Solve for n.<BR>\n" );
document.write( "35. P(n,4) = 40[P(n-1,2)]\r<BR>\n" );
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document.write( "36. P(n,4) = 3[P(n,3)]\r<BR>\n" );
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document.write( "37. n[P(5,3)] = P(7,5)]\r<BR>\n" );
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document.write( "38. 208P(n,2) = P(16,4)\r<BR>\n" );
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document.write( "how exactly do you solve for n? please and thank you.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #87853 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=87853\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve for n.<BR>\n" );
document.write( "35. P(n,4) = 40[P(n-1,2)]<BR>\n" );
document.write( "Using definition of P(n,r)= n!/(n-r)! you get:<BR>\n" );
document.write( "n!/(n-4)! = 40[(n-1)!/(n-3)!]<BR>\n" );
document.write( "Keep in mind n! = n(n-1)! and (n-3)!=(n-3)(n-4)!<BR>\n" );
document.write( "Cancel where you can to get:<BR>\n" );
document.write( "And you get:<BR>\n" );
document.write( "n = 40[1/(n-3)]<BR>\n" );
document.write( "Cross-multiply to get:<BR>\n" );
document.write( "n^2-3n-40=0<BR>\n" );
document.write( "Factor to get:<BR>\n" );
document.write( "(n-8)(n+5)=0<BR>\n" );
document.write( "Solve for n (Keep in mind that n must be positive).<BR>\n" );
document.write( "n = 8<BR>\n" );
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document.write( "36. P(n,4) = 3[P(n,3)]<BR>\n" );
document.write( "Use the definition of P(n,r) <BR>\n" );
document.write( "n!/(n-4)! = 3[n!/(n-3)!]<BR>\n" );
document.write( "Cancel n! of both sides.<BR>\n" );
document.write( "Remember (n-3)!= (n-3)(n-4)!, so cancel (n-4)! of both sides to get:<BR>\n" );
document.write( "1/1 = 3/(n-3)<BR>\n" );
document.write( "Cross-multiply to get:<BR>\n" );
document.write( "3 = n-3<BR>\n" );
document.write( "Solve for n.<BR>\n" );
document.write( "n = 6<BR>\n" );
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document.write( "37. n[P(5,3)] = P(7,5)]<BR>\n" );
document.write( "Apply the definition of P(n,r) to get<BR>\n" );
document.write( "n[5!/(2!] = 7!/(2!)<BR>\n" );
document.write( "Multiply both sides by 2!; Remember 7!= 7*6*5!<BR>\n" );
document.write( "Divide both sides by 5! to get<BR>\n" );
document.write( "n = 7!/5!<BR>\n" );
document.write( "n = 7*6<BR>\n" );
document.write( "n = 42<BR>\n" );
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document.write( "38. 208P(n,2) = P(16,4) <BR>\n" );
document.write( "Use the definition of P(n,r) to get:<BR>\n" );
document.write( "208[n!/(n-2)!] = 16!/(12!)<BR>\n" );
document.write( "208[n(n-1)] = 16*15*14*13<BR>\n" );
document.write( "n(n-1) = 210<BR>\n" );
document.write( "n^2-n-210 = 0<BR>\n" );
document.write( "(n-15)(n+14)=0<BR>\n" );
document.write( "Remember, n must be positive.<BR>\n" );
document.write( "n = 15<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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document.write( "==============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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