document.write( "Question 119880: I've been trying to work this problem, but I'm stumped. I have been trying it with the variable rate equations A=RB and variable rate + fixed rate = total rate. Here is the problem: A 60watt bulb cost 50 cents to buy and 12 cents per day to use (24hrs). Another bulb cost $2.50 to buy and 2 cents per day to use. How many days of use will it take for the cost of the bulbs to be equal and what is the equivalent cost? \n" ); document.write( "
Algebra.Com's Answer #87849 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A 60watt bulb cost 50 cents to buy and 12 cents per day to use (24hrs). Another bulb cost $2.50 to buy and 2 cents per day to use. How many days of use will it take for the cost of the bulbs to be equal and what is the equivalent cost? \n" ); document.write( "---------------------------------- \n" ); document.write( "1st Bulb Cost for x days of use: A(x) = 0.50+0.12x \n" ); document.write( "--------------------- \n" ); document.write( "2nd Bulb Cost for x days of use: B(x) = 2.50 + 0.02x \n" ); document.write( "--------------------- \n" ); document.write( "EQUATION: \n" ); document.write( "When does A(x) = B(x) ? \n" ); document.write( "0.50+0.12x = 2.50 + 0.02x \n" ); document.write( "2.00 = 0.10x \n" ); document.write( "x = 20 days \n" ); document.write( "A and B have equivalent costs for 20 days of use. \n" ); document.write( "------------ \n" ); document.write( "The cost when x=20 days: \n" ); document.write( "A(20) = 0.50 + 0.12*20 = 0.50+2.40 = 2.90 \n" ); document.write( "B(20) = 2.50 + 0.02*20 = 2.50+40 = 2.90 \n" ); document.write( "========================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |