document.write( "Question 119837: Hi, can you help me with this problem?\r
\n" ); document.write( "\n" ); document.write( "Two cyclists, 87 mi apart, start riding towards each other at the same time. One cycles twice as fast as the other. If they meet 2 hr later, at what average speed is each cyclist traveling?
\n" ); document.write( "mi/hr (slower cyclist)
\n" ); document.write( "mi/hr (faster cyclist)
\n" ); document.write( "

Algebra.Com's Answer #87833 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
They are 87 miles apart and they meet somewhere in the middle
\n" ); document.write( "I'll call the distance covered by the slower cyclist \"x\"
\n" ); document.write( "and the distance covered by the faster cyclist \"87-x\"
\n" ); document.write( "Notice when I add these distances, I get \"x+%2B+%2887-x%29+=+87\"
\n" ); document.write( "as I should
\n" ); document.write( "I'll call the speed of the slower cyclist \"s\", Then the speed
\n" ); document.write( "of the faster cyclist would be \"2s\"
\n" ); document.write( "The elapsed time for both of them is 2 hrs
\n" ); document.write( "Now I write distance = speed x time for both of them
\n" ); document.write( "\"x+=+s%2A2\"
\n" ); document.write( "\"87+-+x+=+2s%2A2\"
\n" ); document.write( "Substitute \"2s\" for \"x\" in the 2nd equation
\n" ); document.write( "\"87+-+2s+=+4s\"
\n" ); document.write( "\"6s+=+87\"
\n" ); document.write( "\"s+=+14.5\"
\n" ); document.write( "\"2s+=+29\"
\n" ); document.write( "So, the slower cyclist's average speed is 14.5 mi/hr
\n" ); document.write( "and the faster cyclist's speed is 29 mi/hr
\n" ); document.write( "check answers
\n" ); document.write( "\"87+=+s%2A2+%2B+2s%2A2\"
\n" ); document.write( "\"87+=+14.5%2A2+%2B+29%2A2\"
\n" ); document.write( "\"87+=+29+%2B+58\"
\n" ); document.write( "\"87+=+87\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );