document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=119830>Question 119830</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0130519685/algebrahomeworkh>Algebra 2 with Trigonometry</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> This is an odd consecutive integers word problem. I have to solve it using factoring with the principle zero. The problem says \"The sum of the squares of two consecutive odd positive integers is 394. Find the integers.\" COuld you please help me. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #87826 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=87826\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x=\"first integer\", so x+2=\"next integer\" __ x^2+(x+2)^2=394 __ x^2+x^2+4x+4=394\r<BR>\n" );
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document.write( "2x^2+4x-390=0 __ x^2+2x-195=0 __ factoring gives (x-13)(x+15)=0 </SPAN>\n" );
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