document.write( "Question 18332: Hi all,\r
\n" ); document.write( "\n" ); document.write( "I am having a meltdown with Quadratic equations, vertexes and intercepts. Could someone please help me uunderstand this problem?\r
\n" ); document.write( "\n" ); document.write( "Find the vertex and intercepts for the quadratic function , and sketch its graph:
\n" ); document.write( "y = x^2 - 4x -12\r
\n" ); document.write( "\n" ); document.write( "Thank you very much!
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Algebra.Com's Answer #8782 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Once your quadratic equation is in the standard form:\"ax%5E2+%2B+bx+%2B+c%5D=+0\", the x-coordinate of the vertex is given by \"-b%2F2a\".\r
\n" ); document.write( "\n" ); document.write( "\"-b%2F2a+=+-%28-4%29%2F2%281%29\" = \"4%2F2+=+2\"\r
\n" ); document.write( "\n" ); document.write( "Now find the y-coordinate of the vertex by substituting this value of x (x=2) into the quadratic equation and solve for y.\r
\n" ); document.write( "\n" ); document.write( "\"y+=+%282%29%5E2+-+4%282%29+-+2\"
\n" ); document.write( "\"y+=+4+-+8+-+12\"
\n" ); document.write( "\"y+=+-16\"\r
\n" ); document.write( "\n" ); document.write( "The vertex is at (2, -16)\r
\n" ); document.write( "\n" ); document.write( "The x-intercepts can be found by solving the quadratic equation.\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2+-+4x+-+12+=+0\" Solve by factoring.
\n" ); document.write( "\"%28x%2B2%29%28x-6%29+=+0\" Apply the zero products principle.
\n" ); document.write( "\"x%2B2+=+0\" and/or \"x-6+=+0\"
\n" ); document.write( "If x+2 = 0, then x = -2
\n" ); document.write( "If x-6 = 0, then x = 6
\n" ); document.write( "The x-intercepts are: (-2, 0) and (6, 0)\r
\n" ); document.write( "\n" ); document.write( "See the graph below:
\n" ); document.write( "\"graph%28300%2C200%2C-10%2C10%2C-20%2C10%2Cx%5E2-4x-12%29\"\r
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