document.write( "Question 119809: \r
\n" ); document.write( "\n" ); document.write( "1) how do u write an equation in slope-intercept form of the line that passes through (2,-7) and is parallel to the graph of y=x-2?\r
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\n" ); document.write( "\n" ); document.write( "2) (2,3), y=x+5\r
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\n" ); document.write( "\n" ); document.write( "3) (-5,-4), 2x+3y=-1
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Algebra.Com's Answer #87795 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
Y=mX+b HERE WE HAVE A SLOPE OF 1 & X,Y VALUES OF (2,-7) SO WE USE THESE VALUES IN THE LINE EQUATION & SOLVE FOR b THE Y INTYERCEPT.
\n" ); document.write( "1) -7=1*2+b
\n" ); document.write( "-7=2+b
\n" ); document.write( "b=-7-2
\n" ); document.write( "b=-9
\n" ); document.write( "SO THE LINE EQUATION IS:
\n" ); document.write( "Y=X-9
\n" ); document.write( "-----------------------------------
\n" ); document.write( "2) Y=X+5 (2,3)
\n" ); document.write( "3=2*1+b
\n" ); document.write( "3=2+b
\n" ); document.write( "b=3-2
\n" ); document.write( "b=1
\n" ); document.write( "SO THE LINE EQUATION IS:
\n" ); document.write( "Y=X+1
\n" ); document.write( "-----------------------------------------
\n" ); document.write( "3) 2X+3Y=-1 (-5,-4)
\n" ); document.write( "3Y=-2X-1
\n" ); document.write( "Y=-2X/3-1/3
\n" ); document.write( "-4=-2/3*-5+b
\n" ); document.write( "-4=10/3+b
\n" ); document.write( "b=-4-10/3
\n" ); document.write( "b=(-12-10)/3
\n" ); document.write( "b=-22/3
\n" ); document.write( "SO THE LINE EQUATION IS:
\n" ); document.write( "Y=-2X/3-22/3
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