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document.write( "1) how do u write an equation in slope-intercept form of the line that passes through (2,-7) and is parallel to the graph of y=x-2?\r
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document.write( "2) (2,3), y=x+5\r
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document.write( "3) (-5,-4), 2x+3y=-1 \n" );
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Algebra.Com's Answer #87795 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! Y=mX+b HERE WE HAVE A SLOPE OF 1 & X,Y VALUES OF (2,-7) SO WE USE THESE VALUES IN THE LINE EQUATION & SOLVE FOR b THE Y INTYERCEPT. \n" ); document.write( "1) -7=1*2+b \n" ); document.write( "-7=2+b \n" ); document.write( "b=-7-2 \n" ); document.write( "b=-9 \n" ); document.write( "SO THE LINE EQUATION IS: \n" ); document.write( "Y=X-9 \n" ); document.write( "----------------------------------- \n" ); document.write( "2) Y=X+5 (2,3) \n" ); document.write( "3=2*1+b \n" ); document.write( "3=2+b \n" ); document.write( "b=3-2 \n" ); document.write( "b=1 \n" ); document.write( "SO THE LINE EQUATION IS: \n" ); document.write( "Y=X+1 \n" ); document.write( "----------------------------------------- \n" ); document.write( "3) 2X+3Y=-1 (-5,-4) \n" ); document.write( "3Y=-2X-1 \n" ); document.write( "Y=-2X/3-1/3 \n" ); document.write( "-4=-2/3*-5+b \n" ); document.write( "-4=10/3+b \n" ); document.write( "b=-4-10/3 \n" ); document.write( "b=(-12-10)/3 \n" ); document.write( "b=-22/3 \n" ); document.write( "SO THE LINE EQUATION IS: \n" ); document.write( "Y=-2X/3-22/3 \n" ); document.write( " \n" ); document.write( " |