document.write( "Question 119764: Please help me solve this age problem:
\n" ); document.write( "Lanny and Runiel where born on the same day.
\n" ); document.write( "Lanny is 16 years older than Runiel.
\n" ); document.write( "In 1998, he is 5 times older.
\n" ); document.write( "In what year will she be twice as old? \n" ); document.write( "
Algebra.Com's Answer #87754 by ankor@dixie-net.com(22740)\"\" \"About 
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:
\n" ); document.write( "L is 16 years older than R.
\n" ); document.write( "L = R + 16
\n" ); document.write( ":
\n" ); document.write( "In 1998, he is 5 times older.
\n" ); document.write( "2008 - 1998 = 10 yrs ago
\n" ); document.write( ":
\n" ); document.write( "(L-10) = 5(R-10)
\n" ); document.write( "L - 10 = 5R - 50
\n" ); document.write( "L = 5R - 50 + 10
\n" ); document.write( "L = 5R - 40
\n" ); document.write( "Find out how old they are now:
\n" ); document.write( "Substitute (R+16) for L, solve for R
\n" ); document.write( "R + 16 = 5R - 40
\n" ); document.write( "16 + 40 = 5R - R
\n" ); document.write( "56 = 4R
\n" ); document.write( "R = 56/4
\n" ); document.write( "R = 14 yrs old now
\n" ); document.write( "then
\n" ); document.write( "14 + 16 = 30 yrs old is L now
\n" ); document.write( ":
\n" ); document.write( "In what year will she twice as old?
\n" ); document.write( "Let x = no. of yrs from now she will be twice as old:
\n" ); document.write( "L + x = 2(R+x)
\n" ); document.write( "Substitute their ages in the above equation
\n" ); document.write( "30 + x = 2(14+x)
\n" ); document.write( "30 + x = 28 + 2x
\n" ); document.write( "30 - 28 = 2x - x
\n" ); document.write( "x = 2 yrs; 2010 L is twice as old as R
\n" ); document.write( ":
\n" ); document.write( "This is true in 2010 (2 yrs from now) L will be 32 and R will be 16, \n" ); document.write( "
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