document.write( "Question 119770: Stan invested $5,000, part at 8% and part at 17%. If the total interest at the end of the year is $490, how much did he invest at 8%?\r
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Algebra.Com's Answer #87753 by Caallen2(9)![]() ![]() ![]() You can put this solution on YOUR website! You must form your two variables and two equations.\r \n" ); document.write( "\n" ); document.write( "First we know that the total amount is 5000.\r \n" ); document.write( "\n" ); document.write( "Let the 8% portion of the money invested = x \n" ); document.write( "Let the 17% portion of the money invested = y.\r \n" ); document.write( "\n" ); document.write( "The first equation would be x + y = 5000, because each portion added together will be 5000.\r \n" ); document.write( "\n" ); document.write( "The second equation is derived by the percentages of each portion that will equal the interest acquired which is 490. So the second equation would be:\r \n" ); document.write( "\n" ); document.write( ".08x + .17y = 490\r \n" ); document.write( "\n" ); document.write( "Now we have two equations:\r \n" ); document.write( "\n" ); document.write( "x + y = 5000 and .08x + .17y = 490\r \n" ); document.write( "\n" ); document.write( "Solve by substitution.\r \n" ); document.write( "\n" ); document.write( "x + y = 5000\r \n" ); document.write( "\n" ); document.write( "subtract y from both sides\r \n" ); document.write( "\n" ); document.write( "x = 5000 - y\r \n" ); document.write( "\n" ); document.write( "Now substitute 5000 - y for x in the second equation\r \n" ); document.write( "\n" ); document.write( ".08x + .17y = 490\r \n" ); document.write( "\n" ); document.write( ".08(5000 - y) +.17y = 490\r \n" ); document.write( "\n" ); document.write( "Use distributive property\r \n" ); document.write( "\n" ); document.write( "400 - .08y + .17y = 490\r \n" ); document.write( "\n" ); document.write( "Subtract 400 from both sides and simplify\r \n" ); document.write( "\n" ); document.write( ".09y = 90\r \n" ); document.write( "\n" ); document.write( "divide both sides by .09\r \n" ); document.write( "\n" ); document.write( "y = 1000\r \n" ); document.write( "\n" ); document.write( "now substitute the solution for y into the first equation\r \n" ); document.write( "\n" ); document.write( "x = 5000 - y\r \n" ); document.write( "\n" ); document.write( "x = 5000 - 1000\r \n" ); document.write( "\n" ); document.write( "x = 4000\r \n" ); document.write( "\n" ); document.write( "so your answer will be $4000 was invested at 8% and $1000 was invested at 17%.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |