document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=18322>Question 18322</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Directions: find the measure of the given angles.\r<BR>\n" );
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document.write( "An angle whose supplement is 3 times the measure of its complement. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #8770 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=8770\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the angle =x<BR>\n" );
document.write( "its complement =90-x<BR>\n" );
document.write( "three times the complement =3*(90-x)=270-3x<BR>\n" );
document.write( "its supplement = 180-x<BR>\n" );
document.write( "so <BR>\n" );
document.write( "180-x=270-3x<BR>\n" );
document.write( "3x-x=270-180=90<BR>\n" );
document.write( "2x=90<BR>\n" );
document.write( "x=90/2=45<BR>\n" );
document.write( "so the angle is 45 degrees<BR>\n" );
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