document.write( "Question 119584: Can you help me solve this equation please?\r
\n" ); document.write( "\n" ); document.write( "1. 9/x = 4/3x + 1\r
\n" ); document.write( "\n" ); document.write( "x = ?\r
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Algebra.Com's Answer #87690 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
1. 9/x = 4/3x + 1
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\n" ); document.write( "Assume you mean:
\n" ); document.write( "\"9%2Fx\" = \"4%2F3\"x + 1
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\n" ); document.write( "Multiply equation by 3x to get rid of the denominators:
\n" ); document.write( "3x*\"9%2Fx\" = 3x*\"4%2F3\"x + 3x(1)
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\n" ); document.write( "Cancel out the denominators and you have:
\n" ); document.write( "3(9) = x(4x) + 3x
\n" ); document.write( "27 = 4x^2 + 3x
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\n" ); document.write( "Arrange as a quadratic equation:
\n" ); document.write( "4x^2 + 3x - 27 = 0
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\n" ); document.write( "Factor this to:
\n" ); document.write( "(x + 3)(4x - 9) = 0
\n" ); document.write( "Two solutions
\n" ); document.write( "x = -3
\n" ); document.write( "and
\n" ); document.write( "4x = +9
\n" ); document.write( "x = \"9%2F4\"
\n" ); document.write( "x = 2.25
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\n" ); document.write( "Check solution in original equation using x = +2.25:
\n" ); document.write( "\"9%2F2.25\" = \"4%2F3\"2.25 + 1
\n" ); document.write( " 4 = 3 + 1:; confirms our solutlio
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\n" ); document.write( "You can check the x = -3 solution
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\n" ); document.write( "If I have misinterpreted this problem, it's \"9%2Fx\" = \"4%2F%283x%29\" + 1
\n" ); document.write( "then this is a whole difference animal and will have to be done over.
\n" ); document.write( "Let me know.\r
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