document.write( "Question 119685: 36 gallons of 25% alchol solution means : 25%, or one quarter, of the solution is pure alchol. one quarter of 36 is 9. That solution contains 9 gallons of pure alchol.\r
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\n" ); document.write( "\n" ); document.write( "how many gallons of 30% alchol solution and how many of 60% alchol solution must be mixed to produce 18 gallons of 50% solution
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Algebra.Com's Answer #87673 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
x = number of gallons of 30% alcohol solution
\n" ); document.write( "y = number of gallons of 60% alcohol solution
\n" ); document.write( "In words:
\n" ); document.write( "(alcohol contained in x + alcohol contained in y) / 18 = 50%
\n" ); document.write( "\"%28.3x+%2B+.6y%29+%2F+18+=+.5\"
\n" ); document.write( "and, of course,
\n" ); document.write( "\"x+%2B+y+=+18\"
\n" ); document.write( "In the 1st eqaution,
\n" ); document.write( "\".3x+%2B+.6y+=+9\"
\n" ); document.write( "divide both sides by \".3\"
\n" ); document.write( "\"x+%2B+2y+=+30\"
\n" ); document.write( "\"x+%2B+y+=+18\"
\n" ); document.write( "Now subtract the bottom equation from the top
\n" ); document.write( "\"y+=+12\"
\n" ); document.write( "\"x+%2B+y+=+18\"
\n" ); document.write( "\"x+=+6\"
\n" ); document.write( "6 gallons of the 30% solution must be mixed
\n" ); document.write( "with 12 gallons of the 60% solution
\n" ); document.write( "check answer:
\n" ); document.write( "\"%28.3x+%2B+.6y%29+%2F+18+=+.5\"
\n" ); document.write( "\"%28.3%2A6+%2B+.6%2A12%29+%2F+18+=+.5\"
\n" ); document.write( "\"%281.8+%2B+7.2%29+%2F+18+=+.5\"
\n" ); document.write( "\"9%2F18+=+.5\"
\n" ); document.write( "\".5+=+.5\"
\n" ); document.write( "OK
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