document.write( "Question 119685: 36 gallons of 25% alchol solution means : 25%, or one quarter, of the solution is pure alchol. one quarter of 36 is 9. That solution contains 9 gallons of pure alchol.\r
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document.write( "how many gallons of 30% alchol solution and how many of 60% alchol solution must be mixed to produce 18 gallons of 50% solution \n" );
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Algebra.Com's Answer #87673 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! x = number of gallons of 30% alcohol solution \n" ); document.write( "y = number of gallons of 60% alcohol solution \n" ); document.write( "In words: \n" ); document.write( "(alcohol contained in x + alcohol contained in y) / 18 = 50% \n" ); document.write( " \n" ); document.write( "and, of course, \n" ); document.write( " \n" ); document.write( "In the 1st eqaution, \n" ); document.write( " \n" ); document.write( "divide both sides by \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Now subtract the bottom equation from the top \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "6 gallons of the 30% solution must be mixed \n" ); document.write( "with 12 gallons of the 60% solution \n" ); document.write( "check answer: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "OK \n" ); document.write( " |