document.write( "Question 119676: A boy has 93 cents in pennies, nickels, dimes, and quarters. He has two more quarters than dimes. If he has as many nickles as dimes and as many pennies as quarters, how many of each coin does he have?\r
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Algebra.Com's Answer #87672 by scott8148(6628)\"\" \"About 
You can put this solution on YOUR website!
let x=dimes, so x=nickels, x+2=quarters and x+2=pennies\r
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\n" ); document.write( "\n" ); document.write( "x(10)+x(5)+(x+2)(25)+(x+2)(1)=93\r
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\n" ); document.write( "\n" ); document.write( "10x+5x+25x+50+x+2=93 __ 41x+52=93
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