document.write( "Question 119652: A rectangular garden is to be surrounded by a walkway of constant width. The garden's dimensions are 30 ft by 40 ft. The total area, garden plus walkway, is to be 1800 ft2. What must be the width of the walkway to the nearest thousandth? \n" ); document.write( "
Algebra.Com's Answer #87667 by checkley71(8403)\"\" \"About 
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(30+2X)(40+2X)=1440 X BEING THE WIDTH OF THE WALKWAY.
\n" ); document.write( "1200+80X+60X+4X^2=1440
\n" ); document.write( "4X^2+140X+1200-1440=0
\n" ); document.write( "4X^2+140X-240=0
\n" ); document.write( "4(X^2+35X-60)=0
\n" ); document.write( "USING THE QUADRATIC EQUATION WE GET:\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "X=(-35+-SQRT[35^2-4*1*-60])/2*1
\n" ); document.write( "X=(-35+-SQRT[1225+240])/2
\n" ); document.write( "X=(-35+-SQRT1465])/2
\n" ); document.write( "X=(-35+-38.28)/2
\n" ); document.write( "X=(-35+38.28)/2
\n" ); document.write( "X=3.28/2
\n" ); document.write( "X=1.64 ANSWER.
\n" ); document.write( "X=(-35-38.28)/2
\n" ); document.write( "X=-73.28/2
\n" ); document.write( "X=-36.64 ANSWER.\r
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