document.write( "Question 119655: \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "what is the answer of x(x+3)+2(6x-5)=10?
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #87663 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
X(X+3)=2(6X=5)=10
\n" ); document.write( "X^2+3X+12X-10=10
\n" ); document.write( "X^2+15X-10-10=0
\n" ); document.write( "X^2+15X-20=0
\n" ); document.write( "USING THE QUADRATIC EQUATION x = (-b +- sqrt( b^2-4*a*c ))/(2*a)
\n" ); document.write( "X=(-15+-SQRT[15^2-4*1*-20])/281
\n" ); document.write( "X=(-15+-SQRT[225+80])/2
\n" ); document.write( "X=(-15+-SQRT305)/2
\n" ); document.write( "X=(-15+-17.46)/2
\n" ); document.write( "X=(-15+17.46)/2
\n" ); document.write( "X=-2.46/2
\n" ); document.write( "X=-1.23 ANSWER.
\n" ); document.write( "X=(-15-17.46)/2
\n" ); document.write( "X=-32.46/2
\n" ); document.write( "X=-16.23 ANSWER.\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );