document.write( "Question 18311: The sum of two numbers is 15. Three times one of the numbers is 11 less than five times the other. Find the numbers. \n" ); document.write( "
Algebra.Com's Answer #8766 by yuvaraja(2)![]() ![]() ![]() You can put this solution on YOUR website! x +y = 15 (the sum of two numbers is 15. \n" ); document.write( "3x = 5y-11 ( three times one of the numbers is 11 less than five times the other).\r \n" ); document.write( "\n" ); document.write( "Multiply the first equation by -3.\r \n" ); document.write( "\n" ); document.write( "-3x - 3y = -45. \n" ); document.write( "Rewrite the second equation as \r \n" ); document.write( "\n" ); document.write( "3x - 5y = -11.\r \n" ); document.write( "\n" ); document.write( "Add these two equations:\r \n" ); document.write( "\n" ); document.write( "-8y = -56 \n" ); document.write( "Divide both sides by -8. \n" ); document.write( "y = 7. \n" ); document.write( "Now, plug in this value in the first equation(x+y=15).\r \n" ); document.write( "\n" ); document.write( "x + 7 = 15. \n" ); document.write( "x = 8 \n" ); document.write( "Therefore the two numbers are 7 and 8. \n" ); document.write( " \n" ); document.write( " |