document.write( "Question 119577This question is from textbook Algebra Structure and Method
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document.write( ": Solve by the substitution method
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document.write( "3d+e over 4 = d+1 over 2
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document.write( "d-e over 4 = 1\r
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document.write( "If anyone can answer this problem I would greatly appreciate it. Please and Thank You \n" );
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Algebra.Com's Answer #87653 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Solve by the substitution method \n" ); document.write( "3d+e over 4 = d+1 over 2 \n" ); document.write( "d-e over 4 = 1 \n" ); document.write( "; \n" ); document.write( " \n" ); document.write( "Cross multiply and you have: \n" ); document.write( "2(3d+e) 4(d+1) \n" ); document.write( "6d + 2e = 4d + 4 \n" ); document.write( "6d - 4d + 2e = 4 \n" ); document.write( "2d + 2e = 4 \n" ); document.write( "Simplify, divide by 2: \n" ); document.write( "d + e = 2 \n" ); document.write( "e = (2-d); Use this for substitution \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "Multiply equation by 4 to get rid of that annoying denominator, we have: \n" ); document.write( "d - e = 4 \n" ); document.write( ": \n" ); document.write( "Substitute (2-d) for e in the above equation: \n" ); document.write( "d - (2 - d) = 4 \n" ); document.write( "d - 2 + d = 4 \n" ); document.write( "2d = 4 + 2 \n" ); document.write( "2d = 6 \n" ); document.write( "d = 3 \n" ); document.write( ": \n" ); document.write( "Find e substituting 3 for d in equations; e = (2 - d) \n" ); document.write( "e = 2 - 3 \n" ); document.write( "e = -1 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solutions in the original 1st equation: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "You can check solution in the original 2nd equation \n" ); document.write( " |