document.write( "Question 119577This question is from textbook Algebra Structure and Method
\n" ); document.write( ": Solve by the substitution method
\n" ); document.write( "3d+e over 4 = d+1 over 2
\n" ); document.write( "d-e over 4 = 1\r
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\n" ); document.write( "\n" ); document.write( "If anyone can answer this problem I would greatly appreciate it. Please and Thank You
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Algebra.Com's Answer #87653 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Solve by the substitution method
\n" ); document.write( "3d+e over 4 = d+1 over 2
\n" ); document.write( "d-e over 4 = 1
\n" ); document.write( ";
\n" ); document.write( "\"%28%283d%2Be%29%29%2F4\" = \"%28%28d%2B1%29%29%2F2\"
\n" ); document.write( "Cross multiply and you have:
\n" ); document.write( "2(3d+e) 4(d+1)
\n" ); document.write( "6d + 2e = 4d + 4
\n" ); document.write( "6d - 4d + 2e = 4
\n" ); document.write( "2d + 2e = 4
\n" ); document.write( "Simplify, divide by 2:
\n" ); document.write( "d + e = 2
\n" ); document.write( "e = (2-d); Use this for substitution
\n" ); document.write( ":
\n" ); document.write( "\"%28%28d-e%29%29%2F4\" = 1
\n" ); document.write( "Multiply equation by 4 to get rid of that annoying denominator, we have:
\n" ); document.write( "d - e = 4
\n" ); document.write( ":
\n" ); document.write( "Substitute (2-d) for e in the above equation:
\n" ); document.write( "d - (2 - d) = 4
\n" ); document.write( "d - 2 + d = 4
\n" ); document.write( "2d = 4 + 2
\n" ); document.write( "2d = 6
\n" ); document.write( "d = 3
\n" ); document.write( ":
\n" ); document.write( "Find e substituting 3 for d in equations; e = (2 - d)
\n" ); document.write( "e = 2 - 3
\n" ); document.write( "e = -1
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\n" ); document.write( "Check solutions in the original 1st equation:
\n" ); document.write( "\"%28%283d%2Be%29%29%2F4\" = \"%28%28d%2B1%29%29%2F2\"
\n" ); document.write( "\"%28%283%283%29-1%29%29%2F4\" = \"%28%283%2B1%29%29%2F2\"
\n" ); document.write( "\"%28%288%29%29%2F4\" = \"%28%284%29%29%2F2\"; confirms our solutions
\n" ); document.write( ":
\n" ); document.write( "You can check solution in the original 2nd equation
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