document.write( "Question 18303: I want to know what I need to do to solve this thanks.\r
\n" ); document.write( "\n" ); document.write( "Henry is three times as old as Jane. In 3 years Henry will be x years old. In terms of x, how old will Jane be then?
\n" ); document.write( "Jane's Age then = ? \n" ); document.write( "
Algebra.Com's Answer #8765 by whisper(27)\"\" \"About 
You can put this solution on YOUR website!
Let's break this up.
\n" ); document.write( "Henry = 3 x Jane
\n" ); document.write( "Henry + 3 = x
\n" ); document.write( "What is Jane + 3?
\n" ); document.write( "Let's look at Henry + 3 = x
\n" ); document.write( "Subtract 3 from both sides of the equation
\n" ); document.write( "Henry + 3 - 3 = x - 3
\n" ); document.write( "Henry + 0 = x - 3
\n" ); document.write( "Henry = x - 3
\n" ); document.write( "But Henry also = 3 x Jane
\n" ); document.write( "So we can set
\n" ); document.write( "x-3 = 3 x Jane
\n" ); document.write( "Divide both sides by 3.
\n" ); document.write( "(x-3)/3=(3 x Jane)/3
\n" ); document.write( "(x-3)/3= Jane
\n" ); document.write( "So Jane is (x-3)/3
\n" ); document.write( "But we want Jane + 3
\n" ); document.write( "So
\n" ); document.write( "[(x-3)/3] + 3 = Jane + 3
\n" ); document.write( "To simplify the answer find a common denominator:
\n" ); document.write( "(x-3)/3 + 9/3
\n" ); document.write( "(x-3 + 9)/3
\n" ); document.write( "(x+6)/3 This is ok for an answer or you could write it as:
\n" ); document.write( "x/3 + 2 Either is acceptable.\r
\n" ); document.write( "\n" ); document.write( "Don't hesitate to ask if you have further questions!
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