document.write( "Question 119612: Angelo, Brandon, and Carl work in the same office. Angelo's age is 4 years more than twice Carl's age. Brandon is 5 years younger than Carl. The average of the 3 ages is 41. Find the age of each of the men. \n" ); document.write( "
Algebra.Com's Answer #87612 by stanbon(75887)\"\" \"About 
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Angelo, Brandon, and Carl work in the same office. Angelo's age is 4 years more than twice Carl's age. Brandon is 5 years younger than Carl. The average of the 3 ages is 41. Find the age of each of the men.\r
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\n" ); document.write( "Let Angelo be a; Brandon is b ; Carl is c
\n" ); document.write( "EQUATION:
\n" ); document.write( "a = 2c+4
\n" ); document.write( "b = c-5
\n" ); document.write( "(1/3)(a+b+c) = 41
\n" ); document.write( "-----------------
\n" ); document.write( "Rearrange:
\n" ); document.write( "a + 0 - 2c = 4
\n" ); document.write( "0 + b -c --5
\n" ); document.write( "a + b + c = 123
\n" ); document.write( "-------------------
\n" ); document.write( "Using the Matrix function of a TI calculator I get:
\n" ); document.write( "a= 66
\n" ); document.write( "b= 26
\n" ); document.write( "c= 31
\n" ); document.write( "==========
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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