document.write( "Question 119561: can you please explain this to me in step by step form so hopefully i can understand this.\r
\n" ); document.write( "\n" ); document.write( "log x 9/4 =2\r
\n" ); document.write( "\n" ); document.write( "please help me \r
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\n" ); document.write( "julie
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Algebra.Com's Answer #87599 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Does this say: \"log base x of 9/4 equals 2\"? If it does, then...\r
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\n" ); document.write( "\n" ); document.write( "\"log%28x%2C%289%2F4%29%29=2\" Start with the given equation. \r
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\n" ); document.write( "\n" ); document.write( "\"x%5E%282%29=9%2F4\" Rewrite the equation using the property: \"log%28b%2C%28x%29%29=y\" ====> \"b%5Ey=x\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=sqrt%289%2F4%29\" Take the square root of both sides. Since you cannot take the log of a negative number, I'm going to exclude the negative answer.\r
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\n" ); document.write( "\n" ); document.write( "\"x=sqrt%289%29%2Fsqrt%284%29\" Break up the square root\r
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\n" ); document.write( "\n" ); document.write( "\"x=%283%29%2Fsqrt%284%29\" Simplify \"sqrt%289%29\" to get \"3\" \r
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\n" ); document.write( "\n" ); document.write( "\"x=%283%29%2F%282%29\" Simplify \"sqrt%284%29\" to get \"2\" \r
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\n" ); document.write( "\n" ); document.write( "So our answer is \"x=%283%29%2F%282%29\"
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