document.write( "Question 119545This question is from textbook Algebra Structure and Method
\n" ); document.write( ": solve by the substitution method\r
\n" ); document.write( "\n" ); document.write( "3d+e/4= d+1/2
\n" ); document.write( "d-e/4 = 1\r
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\n" ); document.write( "\n" ); document.write( "If anyone can answer this math problem I would deeply appreciate it. Please and Thank You \n" ); document.write( "
Algebra.Com's Answer #87592 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
d-e/4=1
\n" ); document.write( "-e/4=1-d
\n" ); document.write( "e/4=d-1 now replace e/4 by (1-d) in the other equation.
\n" ); document.write( "3d+(d-1)=d+1/2
\n" ); document.write( "3d+d-1=d+.5
\n" ); document.write( "3d+d-d=1+.5
\n" ); document.write( "3d=1.5
\n" ); document.write( "d=1.5/3
\n" ); document.write( "d=.5 answer.
\n" ); document.write( "e/4=.5-1
\n" ); document.write( "e/4=-.5
\n" ); document.write( "e=4*-.5
\n" ); document.write( "e=-2 answer.
\n" ); document.write( "proof
\n" ); document.write( ".5-(-2/4)=1
\n" ); document.write( ".5+.5=1
\n" ); document.write( "1=1\r
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