document.write( "Question 119382: \r
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document.write( "A plane flies 720 mi against a steady 30-mi/h headwind
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document.write( "and then returns to the same point with the wind. If the entire trip takes 10 h, what is the plane’s speed in still air? \n" );
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Algebra.Com's Answer #87589 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! 720/(r-30)+720/(r+30)=10 \n" ); document.write( "[720(r+30)+720(r-30)]/(r^2-900)=10 \n" ); document.write( "(720r+21,600+720r-21,600)/(r^2-900)=10 now cross multiply \n" ); document.write( "10(r^2-9000)=1440r \n" ); document.write( "10r^2-1440r-9000=0 \n" ); document.write( "10(r^2-144r-900)=0 \n" ); document.write( "10(x-150)(x+6)=0 \n" ); document.write( "x-150=0 \n" ); document.write( "x=150 for the speed of the airplane. \n" ); document.write( "proof \n" ); document.write( "720/(150-30)+720/(150+30)=10 \n" ); document.write( "720/120+720/180=10 \n" ); document.write( "6+4=10 \n" ); document.write( "10=10 \n" ); document.write( " \n" ); document.write( " |