document.write( "Question 119488: original problem: 5x^2-30x+40=0
\n" ); document.write( " work:
\n" ); document.write( "5x^2-30x=-40
\n" ); document.write( "x^2-6x=-8
\n" ); document.write( "x^2-6x+9=-8+9\r
\n" ); document.write( "\n" ); document.write( "Please help. I keep getting lost. Could you show me how to work this problem step by step? I already have the answer, so I'm not looking for that, just how to do it. The answer is x=2, x=4
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Algebra.Com's Answer #87535 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve for x:
\n" ); document.write( "\"5x%5E2-30x%2B40+=+0\" First, you can factor a 5 from this quadratic equation.
\n" ); document.write( "\"5%28x%5E2-6x%2B8%29+=+0\" Now apply the \"zero product principle\": If\"a%2Ab+=+0\"then either\"a+=+0\"or\"b+=+0\" or both.
\n" ); document.write( "So...
\n" ); document.write( "If \"5%28x%5E2-6x%2B8%29+=+0\"then either \"5+=+0\" (obviously not true!) or \"x%5E2-6x%2B8+=+0\". Ok, so...
\n" ); document.write( "\"x%5E2-6x%2B8+=+0\" Solve this by factoring:
\n" ); document.write( "\"%28x-2%29%28x-4%29+=+0\" ...again, apply the \"zero product principle\"...
\n" ); document.write( "If \"x-2+=+0\" then \"x+=+2\" or
\n" ); document.write( "If \"x-4+=+0\" then \"x+=+4\"
\n" ); document.write( "The solutions are, as you have stated, x = 2 or x = 4.
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