document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=119484>Question 119484</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The four oldest people in Golden City have lived a total of 384 years put together. The difference in ages for the youngest and the second oldest is 14. The second youngest is 3 years older than the youngest. The oldest is 20 years older than the average of the second oldest and youngest. What are their ages?\r<BR>\n" );
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document.write( "The ages are ____, _____, _____, and  _____ . </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #87531 by </B><A HREF=/tutors/aboutme.mpl?userid=MaxLiebling><B>MaxLiebling(13)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MaxLiebling><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=87531\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I call them A(dam) [youngest], B(ert) [second youngest], C(laus) [second oldest] and D(iddl) [oldest].<BR>\n" );
document.write( "total of 384 years: A+B+C+D = 384 (1)<BR>\n" );
document.write( "The difference in ages for the youngest and the second oldest is 14:<BR>\n" );
document.write( "C-A = 14 -> C = A + 14 (2)<BR>\n" );
document.write( "The second youngest is 3 years older than the youngest:<BR>\n" );
document.write( "B = A+3 (3)<BR>\n" );
document.write( "The oldest is 20 years older than the average of the second oldest and youngest:<BR>\n" );
document.write( "D = (C+A)/2 + 20 (4)<BR>\n" );
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document.write( "A+B+C+D = 384 <BR>\n" );
document.write( "use (3): 384 = A+B+C+D = A+ A+3 +C+D = 2A+C+D+3<BR>\n" );
document.write( "use (4): 384 = 2A+C+D+3 = 2A+C+ (C+A)/2 + 20 +3 = 2A+C +C/2 + A/2 +23<BR>\n" );
document.write( "-23 (384-23=361), than multiply by 2: 722 = 4A+2C + C + A = 5A + 3C<BR>\n" );
document.write( "use (2): 722 = 5A + 3*(A+14) = 5A+3A+42<BR>\n" );
document.write( "-42: 680 = 8A<BR>\n" );
document.write( "-> A = 680/8 = 85<BR>\n" );
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document.write( "use (2):<BR>\n" );
document.write( "C = A+14 = 85+14 = 99<BR>\n" );
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document.write( "use (3):<BR>\n" );
document.write( "B = A+3 = 85+3 = 88<BR>\n" );
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document.write( "A+B+C = 85 + 88 + 99 = 272<BR>\n" );
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document.write( "use (1):<BR>\n" );
document.write( "272 + D = 384<BR>\n" );
document.write( "-> D = 384-272 = 112<BR>\n" );
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document.write( "The ages are 85, 88, 99, and 112.<BR>\n" );
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