document.write( "Question 119477: Good evening ma'am or sir will you please help on how to solve this problem involving expressions with exponents? Thank you very much.\r
\n" ); document.write( "\n" ); document.write( "4). An electric current of one (1) ampere will deposit 0.0011180 g of silver each second from a water solution of silver nitrate. How many grams of silver will be deposited if the current is 1 * 10^-1 amperes and the time is one (1) hour and 20 minutes? \r
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Algebra.Com's Answer #87530 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
Use Faraday's equation for electrolysis is \"+m+=+k%2AI%2At\"\r
\n" ); document.write( "\n" ); document.write( "That is:
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\n" ); document.write( "\"mass_+in_+grams+=+electrochemical_+equivalent+%2A+current+%2A+time\"\r
\n" ); document.write( "\n" ); document.write( "or\r
\n" ); document.write( "\n" ); document.write( "\"m+=+k+%2AI+%2A+t\"\r
\n" ); document.write( "\n" ); document.write( "where\r
\n" ); document.write( "\n" ); document.write( " \"m=+mass\" in \"grams\"\r
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\n" ); document.write( "\n" ); document.write( "\"k=+electrochemical_+equivalent+\"……..atom weight divided by valence times 96,500; \"k\" for silver is \"107.88+%2F96500\" or = \"0.001118\"\r
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\n" ); document.write( "\n" ); document.write( "\"I=+current\"……………….. in amps\r
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\n" ); document.write( "\n" ); document.write( "\"t=+time\"…………………….. in seconds\r
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\n" ); document.write( "\n" ); document.write( "given:\r
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\n" ); document.write( "\n" ); document.write( "\"k+=+0.001118\"\r
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\n" ); document.write( "\n" ); document.write( "\"I=+1+%2A+10%5E-1+%2AA+\"……………….. in amps\r
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\n" ); document.write( "\n" ); document.write( "\"t=+1+h+20+min+\"……………………..should be in seconds, and that will be
\n" ); document.write( "\"3600s+%2B1200s+=+4800s\"\r
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\n" ); document.write( "\n" ); document.write( "So, we will have:\r
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\n" ); document.write( "\n" ); document.write( "\"m+=+k+%2AI+%2A+t\"\r
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\n" ); document.write( "\n" ); document.write( "\"m+=+0.001118+%2A10%5E-1++%2A+4800+\"\r
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\n" ); document.write( "\n" ); document.write( "\"m+=+0.001118+%2A+1%2F10++%2A+4800+\"\r
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\n" ); document.write( "\n" ); document.write( "\"m+=+0.001118+%2A+.1++%2A+4800+\"\r
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\n" ); document.write( "\n" ); document.write( "\"m+=+0.53664g\"\r
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