document.write( "Question 119472: Construction. A garden area is 30 ft long and 20 ft wide. a path of uniform width is set around the edge. If the remaining garden area is 400 ft^2 , what is the width of the path? \r
\n" ); document.write( "\n" ); document.write( "So if I squared 20, 30, 400 And I get something like 30 ft, would I be terribly wrong?
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Algebra.Com's Answer #87510 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
I THINK YOU BEST APPROACH ON WORD PROBLEMS IS TO LAY THEM OUT IN AN ORDERLY FASHION IDENTIFYING WHAT NEEDS TO BE DETERMINED AS YOU GO. I HAVE TRIED TO DO THIS BELOW:
\n" ); document.write( "Area(A)=Length(l) times Width(w) or A=l*w\r
\n" ); document.write( "\n" ); document.write( "Let w=the uniform width of the path. Note that the path is inside the original garden\r
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\n" ); document.write( "\n" ); document.write( "Note: draw the garden and path and the statement below will be obvious.
\n" ); document.write( "Area of garden after path is put in= (20-2w)*(30-2w) =600-100w+4w^2 and this we are told equals 400 ft^2. So:\r
\n" ); document.write( "\n" ); document.write( "600-100w+4w^2=400 subtract 400 from both sides\r
\n" ); document.write( "\n" ); document.write( "600-400-100w+4w^2=400-400 collect like terms\r
\n" ); document.write( "\n" ); document.write( "4w^2-100w+200=0 divide each term by 4\r
\n" ); document.write( "\n" ); document.write( "w^2-25w+50=0 quadratic in standard form. Solve using the quadratic formula:
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "\"x+=+%2825+%2B-+sqrt%28-25%5E2-4%2A1%2A50+%29%29%2F%282%2A1%29+\"
\n" ); document.write( "\"x+=+%2825+%2B-+sqrt%28+625-200+%29%29%2F%282%29+\"
\n" ); document.write( "\"x+=+%2825+%2B-+sqrt%28+425%29%29%2F%282%29+\"
\n" ); document.write( "\"x+=+%2825+%2B-+20.6%29%2F%282%29+\"
\n" ); document.write( "\"x+=+%2825+%2B+20.6%29%2F%282%29+\"
\n" ); document.write( "\"x+=+%2845.6%29%2F%282%29+\"
\n" ); document.write( "\"x=22.8\" ft----------------------too large-- gives a negative value for length and width--- not a correct answer
\n" ); document.write( "and
\n" ); document.write( " \"x+=+%2825+-+20.6%29%2F%282%29+\"
\n" ); document.write( "\"x+=+%284.4%29%2F%282%29+\"
\n" ); document.write( "\"x=2.2\" ft----ans
\n" ); document.write( "(30-2*2.2)(20-2*2.2)=400
\n" ); document.write( "(30-4.4)(20-4.4)=400
\n" ); document.write( "25.6*15.6=400\r
\n" ); document.write( "\n" ); document.write( "~~~400=400\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r
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