document.write( "Question 119440: Find the solution set in interval notation: x+12/x+2 <= 3
\n" ); document.write( "Thank you so much!!! :D \n" ); document.write( "
Algebra.Com's Answer #87498 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
(x+12)/(x+2)-3 <= 0
\n" ); document.write( "----------------
\n" ); document.write( "Find the values x cannot take:
\n" ); document.write( "x=-2
\n" ); document.write( "------------------
\n" ); document.write( "Draw a number line; x=-2
\n" ); document.write( "Find a test point in each interval to find the solution set:
\n" ); document.write( "If x=-3, (-3+12)/(-3+2)-3<-0, true
\n" ); document.write( "If x=-1, (-1+12)/(-1+2)-3<=0, false
\n" ); document.write( "--------------
\n" ); document.write( "Solution: (-inf,-2)
\n" ); document.write( "======================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "---------------
\n" ); document.write( " \n" ); document.write( "
\n" );