document.write( "Question 119390: FACTOR EACH EXPRESSION:\r
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Algebra.Com's Answer #87461 by jim_thompson5910(35256) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( " $\"8z%5E2-4z%2B10z-5\"$ Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( " $\"%288z%5E2-4z%29%2B%2810z-5%29\"$ Group like terms\r
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\n" ); document.write( "\n" ); document.write( " $\"4z%282z-1%29%2B5%282z-1%29\"$ Factor out the GCF $\"4z\"$ out of the first group. Factor out the GCF $\"5\"$ out of the second group\r
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\n" ); document.write( "\n" ); document.write( " $\"%284z%2B5%29%282z-1%29\"$ Since we have the common term $\"2z-1\"$ , we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So $\"8z%5E2-4z%2B10z-5\"$ factors to $\"%284z%2B5%29%282z-1%29\"$
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