document.write( "Question 119381: \r
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document.write( "How much pure alcohol must be added to 40 oz of a 25%
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document.write( "solution to produce a mixture that is 40% alcohol? \n" );
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Algebra.Com's Answer #87456 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! .25*40+x=.4(x+40) \n" ); document.write( "10+x=.4x+16 \n" ); document.write( "x-.4x=16-10 \n" ); document.write( ".6x=6 \n" ); document.write( "x=6/.6 \n" ); document.write( "x=10 oz of pure alcohol is needed. \n" ); document.write( "proof \n" ); document.write( ".25*40+10=.4*50 \n" ); document.write( "10+10=20 \n" ); document.write( "20=20 \n" ); document.write( " |